Deriving Equation for Triangular Duct Flow

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In summary, the conversation discusses the derivation of an equation that describes the flow in a triangular duct. The assumptions made include laminar flow, steady state, constant properties, no slip at walls, and incompressible flow. There is a closed form analytical solution available, but the boundary conditions may be difficult to define. One approach is to calculate the Hydraulic Diameter of the pipe and work in cylindrical coordinates.
  • #1
jaap de vries
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Dear friends,

Does anybody now how I derive the equation that describes the flow in a triangular duct.
making the assumptions
Laminar
steady
constant properties
no slip at walls
incompressible

Jaap
 
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  • #2
jaap de vries said:
Dear friends,
Does anybody now how I derive the equation that describes the flow in a triangular duct.
making the assumptions
Laminar
steady
constant properties
no slip at walls
incompressible
Jaap

The equation you shl

Neglect unsteady term of N-S equations: [tex]0=-\nabla P +\mu\nabla^2\overline{u}[/tex]. This is the equation for viscous and incompressible flow. The main problem you have is to establish a coordinate system. Solving this problem in cylindrical or cartesian coordinates may be a little bit difficult. A nice engineering approach is to calculate the Hydraulic Diameter of the pipe (which holds [tex]\dot {m}=\rho UA[ /tex] assuming a round pipe), and work in cylindrical coordinates with that average diameter.
 
  • #3
Thank you Claussius,

That is a possibility however, I know there is a closed form analytical solution to this problem the initial N-S equation is correct but the boundary conditions are not so easely defined.

Jaap
 

1. What is the equation for flow through a triangular duct?

The equation for flow through a triangular duct is given by the Manning equation, which is Q = (1.49/n) * A * R^(2/3) * S^(1/2), where Q is the flow rate, n is the Manning roughness coefficient, A is the cross-sectional area of the duct, R is the hydraulic radius, and S is the slope of the duct.

2. How is the cross-sectional area of a triangular duct calculated?

The cross-sectional area of a triangular duct can be calculated using the formula A = (b * h)/2, where b is the base length and h is the height of the triangle.

3. What is the Manning roughness coefficient used for in the equation?

The Manning roughness coefficient, also known as the Manning's n, is used to account for the roughness of the duct's interior surface. It takes into consideration factors such as the material of the duct and the presence of any obstructions that may affect the flow of water.

4. How is the hydraulic radius calculated for a triangular duct?

The hydraulic radius for a triangular duct can be calculated using the formula R = A/P, where A is the cross-sectional area of the duct and P is the wetted perimeter. The wetted perimeter is the sum of the three sides of the triangle.

5. Is the Manning equation applicable for all types of fluids?

No, the Manning equation is specifically used for open channel flow of water. It is not applicable for other types of fluids, such as gases or oil. Other equations, such as the Darcy-Weisbach equation, are used for flow of different fluids in closed conduits.

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