- #1

jbowers9

- 89

- 1

## Homework Statement

I recently tried to do the following integral:

a

_{n}= ∫√(2/a) sin(n∏x/a) cosh(x) dx

x=0 to x=a

## Homework Equations

a

_{n}= ∫√(2/a) sin(βx) cosh(x) dx

β = n∏/a

sin(βx) = ½i(e

^{iβx}– e

^{-iβx})

cosh(x) = ½(e

^{x}+ e

^{-x})

## The Attempt at a Solution

a

_{n}= ¼ i √(2/a)∫ (e

^{iβx}– e

^{-iβx}) (e

^{x}+ e

^{-x})

after all is said and done, I get;

a

_{n}= √(2/a)[(a

^{2}sin(n∏)sinh(a) – acos(n∏)cosh(a) + n∏a)/(n

^{2}∏

^{2}+ a

^{2})]

The text, “Quantum Mechanics Demystified”, however, gets;

a

_{n }= √(2/a)[a(n∏cos(n∏)cosh(a) + sin(n∏)sinh(a))/( n

^{2}∏

^{2}+ a

^{2})]

Which is correct? And why?

## Homework Statement

## Homework Equations

## The Attempt at a Solution

## Homework Statement

## Homework Equations

## The Attempt at a Solution

## Homework Statement

## Homework Equations

## The Attempt at a Solution

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