Tricky integral?

  • Thread starter Grand
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  • #1
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Homework Statement


Could anyone show me how integral (5) in this document is calculated. I've been trying and trying but nothing good came out.

[tex]\theta=\frac{\rho}{R}\int\sqrt{\frac{R^2-r^2}{r^2-\rho^2}}\frac{dr}{r}=[/tex]
[tex]=\arctan\left(\frac{R}{\rho}\sqrt{\frac{r^2-\rho^2}{R^2-r^2}\right)-\frac{\rho}{R}\arctan\sqrt{\frac{r^2-\rho^2}{R^2-r^2}[/tex]

Thank you in advance.


Homework Equations





The Attempt at a Solution

 
Last edited:

Answers and Replies

  • #2
dextercioby
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Hi, the article is not free to view. Please, write the integral yourself, or post a screenshot from the article containing it.
 
  • #3
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Thank you, fixd it.
 

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