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Tricky integral

  1. Apr 4, 2012 #1
    I don't know if this is very basic, but I'm having trouble with the integral:

    ∫-sin(t)2 + cos(t)2 dt from [0;∏/4]

    Have tried substituting sin(t)2 = cos(t)2 - 1 but didn't really make things easier as it's the exponent that troubles me. How do you solve this integral the easiest way?
     
  2. jcsd
  3. Apr 4, 2012 #2

    Mark44

    Staff: Mentor

    cos2(t) - sin2(t) = cos(2t)
     
  4. Apr 4, 2012 #3

    Mark44

    Staff: Mentor

    Also, when you start a thread, don't just blow away the template parts.
     
  5. Apr 4, 2012 #4

    Ray Vickson

    User Avatar
    Science Advisor
    Homework Helper

    Please try to follow standard notation; the square of a quantity x is x^2, not x2. Alternatively, you could use the "SUP" command, to get x2, which was typed in as x[S U P ]2[/ S U P] but with all the spaces removed.

    RGV
     
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