Tricky integral

  • #1
relatively_me
18
0
I'm having trouble finding an integral table w/ this integral, or understanding a method to solve it...any hints would really be appreciated (the book directs us to use integral tables)

Int[e^(x^2) dx] limits->{-inf, +inf}

Thanks in advance
 

Answers and Replies

  • #2
fahd
40
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take x^2=t and proceed by parts...its fairly simple
 
  • #3
relatively_me
18
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thanks, i'll try that now
 
  • #4
relatively_me
18
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2x*e^(x^2) + x^2*e^(x^2)?
 
  • #5
Pietjuh
76
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You don't even have to calculate it to see it diverges to infinity, since exp(x^2) is a strictly increasing function on (0,inf), and is also positive for negative x.
 
  • #6
amcavoy
665
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Pietjuh said:
You don't even have to calculate it to see it diverges to infinity, since exp(x^2) is a strictly increasing function on (0,inf), and is also positive for negative x.
Are you sure the problem wasn't with a negative x2?

[tex]\int_{-\infty}^{\infty}e^{-x^2}\,dx=\sqrt{\pi}[/tex]

Alex
 
  • #8
HallsofIvy
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fahd said:
take x^2=t and proceed by parts...its fairly simple

I have no idea what you mean by that! What "parts" would you use? What would be u and what dv?

As others have pointed out, the infinite integral, as stated, does not exist. If that were [tex]e^{-x^2}[/tex] then it would be possible but certainly not "fairly simple"- there is no elementary anti-derivative.
 
  • #9
Taviii
9
0
e^x^2=e^x*e^x
so
e^x=t
e^xdx=dt......replace in your exercesise and it should be easy from now on!
 
  • #10
HallsofIvy
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Yes, if I had to integrate
[tex]\int (e^x)^2dx[/tex]
I guess I could do that- although I think I would be more likely to simply write
[tex](e^x)^2= e^{2x}[/tex]
and integrate that. HOWEVER, the integral asked about was
[tex]\int e^{x^2}dx[/tex]
and it is well known that that has no elementary anti-derivative.
 
  • #11
1800bigk
42
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if you are in analysis it can be solved using riemann-stieltjes or lebesgue theory, I saw this problem before and there was a theorem we used, it has slipped my memory.

it was something like if f(x) is differentiable on [a,b] and f prime is continuous on [a,b] then you can convert the integrand to somethin easier to integrate (i forget the rest) sorry
 
Last edited:
  • #12
what
91
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Yea you can put it into http://integrals.wolfram.com and it gives you an answer that has in it the "imaginary error function", i take this to mean that the described integral won't be solvable by any normal means, so if it is just about whether or not it diverges then this is pretty simple because it is obvious that the integral diverges.
 
  • #13
darkar
187
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what said:
Yea you can put it into http://integrals.wolfram.com and it gives you an answer that has in it the "imaginary error function", i take this to mean that the described integral won't be solvable by any normal means, so if it is just about whether or not it diverges then this is pretty simple because it is obvious that the integral diverges.

I got this....sqrt(pi)Erfi(x)/2

What is that Erfi?
 
  • #14
benorin
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Erfi is the imaginary error function above quoted by what (cool psuedonym).
 
  • #15
BerkMath
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Taviii said:
e^x^2=e^x*e^x
so
e^x=t
e^xdx=dt......replace in your exercesise and it should be easy from now on!

My guess is that Tavi will think things through before typing incorrect answers, next time.
 
  • #16
HallsofIvy
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benorin said:
Erfi is the imaginary error function above quoted by what (cool psuedonym).

All my errors are imaginary!
 
  • #17
darkar
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Umm..........
 

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