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Tricky intergral

  1. Nov 12, 2006 #1


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    Which substituation would I need to use for this intergral;

    [y.du/(y^2 + (x - u)^2)]
  2. jcsd
  3. Nov 12, 2006 #2


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    The integrand looks like [tex]1/(1+x^2)[/tex] which has antiderivative arctan(x). Try to make substitutions to match that expression.
  4. Nov 13, 2006 #3


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    Got it, take the y out the intergral, make b=x-u then db=-du sub in and use the arctan intergral, getting -tan^-1((x-u)/y)
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