- #1
vijay123
- 122
- 0
hi,
i got 2 problems that are really hard to solve. i don't know wether they are trick question or they just can be incorperated in a formula.i have taken days to solve them but in vain. please help!
a) 10(3^(2x+1)) = 2^(4x-3)
b) (2/3x)^(log2) = (9x)^(log3)
thanks you very much
i got 2 problems that are really hard to solve. i don't know wether they are trick question or they just can be incorperated in a formula.i have taken days to solve them but in vain. please help!
a) 10(3^(2x+1)) = 2^(4x-3)
b) (2/3x)^(log2) = (9x)^(log3)
thanks you very much