- #1

- 324

- 0

x+y+z=0

x

^{3}+y

^{3}+z

^{3}=3

x

^{5}+y

^{5}+z

^{5}=15

x

^{2}+y

^{2}+z

^{2}=?

An answer must be supported with justification (so that I know that you didn't guess and get lucky).

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- #1

- 324

- 0

x+y+z=0

x

x

x

An answer must be supported with justification (so that I know that you didn't guess and get lucky).

- #2

- 45

- 0

I'm going to ask my math teacher :)

- #3

- 101

- 0

x+y+z=0

x^{3}+y^{3}+z^{3}=3

x^{5}+y^{5}+z^{5}=15

x^{2}+y^{2}+z^{2}=?

An answer must be supported with justification (so that I know that you didn't guess and get lucky).

Unless you can demonstrate that there is a clever shortcut to this problem which would raise it to the level of a brainteaser, this is just a set of simultaneous equations which is easily solvable with, for example, the Wolfram Alpha website.

- #4

- 324

- 0

I had no idea that such a site even existed.Unless you can demonstrate that there is a clever shortcut to this problem which would raise it to the level of a brainteaser, this is just a set of simultaneous equations which is easily solvable with, for example, the Wolfram Alpha website.

- #5

- 45

- 0

How do they solve it ?

- #6

- 31

- 0

I got the answer but i cant´t get the values os x, y and z, but i got that x.y.z =

x.y.z=1

- #7

- 31

- 0

x= 2 cos (20)

y= 2 cos (140)

z= 2 cos (260)

the answer to the question is 6

y= 2 cos (140)

z= 2 cos (260)

the answer to the question is 6

- #8

- 31

- 0

At a glance:

x = -y-z

x<2 and positive

y not equal z

y and z are negative

x.y.z = 1

x<2 and positive

y not equal z

y and z are negative

x.y.z = 1

- #9

- 31

- 0

^2 = 14 --> ?

^3 = 18 --> 3

^5 = 210 --> 15

so 14 . 18 . 15 = ? . 3 . 210

? = 6

That´s the tricky way...