- #1
Sammon
- 2
- 0
Would someone be kind enough to show the working for expressing the following in partial fractions:
[tex]
\frac{x^2}{(x-1)(x+1)}
[/tex]
I believe the answer is
[tex]\frac{x^2}{(x-1)(x+1)} \equiv 1 + \frac{1}{2(x-1)} - \frac{1}{2(x+1)}[/tex]
Thanks in advance,
Sammon Jnr
[tex]
\frac{x^2}{(x-1)(x+1)}
[/tex]
I believe the answer is
[tex]\frac{x^2}{(x-1)(x+1)} \equiv 1 + \frac{1}{2(x-1)} - \frac{1}{2(x+1)}[/tex]
Thanks in advance,
Sammon Jnr