Hello everyone...im feeling lost on this question. The answer is 2/3. But i don't know how they are getting it. Six new employees, two of whom are married to eachother, are to be assigned six desks that are lined up in a row. If the assignment of employees to desks is made randomly, what is the probability that the married couple will have nonadjacent desks? (Hint: First find the probability that the coup will have adjacent desks, and then subtract this number from 1.) Well I think i figured out how many ways the 2 married couple will end up in adjacent desks by the following: I let A, B, C, D, E, F stand for the 6 employee's, i'm going to assume A and B are the married couple. So... [number of ways to place 6 together keeping A and B side by side] = [Number of ways to arrange [A B] C D E F ] + [ number of ways to arrange [B A] C D E F] = 5! + 5! = 120 + 120 = 240 ways to arrange the 6 employee's keeping A and B together (the married couple). Now i know the total number of ways to place the 6 people together wolud be 6! = 720. So the probability that the couple will have adjacent desks is: P = N(E)/N(S) = 240/720 = 1/3; 1 - 1/3 = 2/3. I seeemed to figure the problem out while typing this hah, oh well that works! I should do this more often.