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Homework Help: Tricky problem

  1. Nov 27, 2006 #1
    Consider the one dimentional motion of a particle in the potential

    [tex]V(x)=D(e^{-2ax}-2e^{-ax})[/tex].

    I'm supposed to obtain the expressions for x as a function of time separately for the cases that the total energy E is positive, zero or negative.

    I have used

    [tex]\frac{1}{2}m\dot{x}^2 + V(x) - E = 0[/tex]

    and got the integral

    [tex]\int \sqrt{\frac{m}{2(E-V(x))}}dx[/tex]

    to solve.

    First, is this a correct method?

    Second, how do I solve this integral?
     
  2. jcsd
  3. Nov 28, 2006 #2

    dextercioby

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    Homework Helper

    Yes, it looks okay. The same kinda substitution i advised in the thread on turning points would be useful.

    Daniel.
     
  4. Nov 28, 2006 #3
    You guess a solution.
     
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