A projectile is shot from the edge of a cliff h = 265 m above ground level with an initial speed of v0 = 105 m/s at an angle of 37.0° with the horizontal(adsbygoogle = window.adsbygoogle || []).push({});

Xo=0m Yo=0m

X= 1361m YTop of Cliff=265m

Ax= 0m/s/s Ay=-9.8m/s/s

Vo= 105 m/s Vx= 83.86 m/s

Theta= 37.0

T= 16.23 s

I need to determine the vertical component of the velocity at the point directly above the ground before impact. I calculated the vertical velocity from launch to the maximum Y to be 63.2 m/s.

I tried calculating this several ways but I know all of the following are wrong:

v=105+(-9.8)(16.23)= -54

V^2=105^2+2(-9.8)(0-265)= 127.35

V^2=0^2+2(-9.8)(0-265)= 72.07

I know I'm missing something here but I cant quite put my finger on it. Could someone direct me to what ever this is?

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# Tricky Projectile Motion

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