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Tricky Triangle

  1. Oct 29, 2004 #1
    Here is a file i created of a problem I was asked if see if you have what it takes:
     

    Attached Files:

  2. jcsd
  3. Oct 29, 2004 #2
    I hope you don't find this too little help but first fill in all the angles you know. After that, law of sines is your friend.
     
  4. Oct 29, 2004 #3
    I believe that to be so, i just haven't been able to find the angle 3 or angle 2, but maybe i am overlooking something.i will study it some more.
     
  5. Oct 30, 2004 #4
    You can find 2 equations that involve angles 2 and 3, then you have two equations and two unknowns
     
  6. Oct 30, 2004 #5
    Oh Really, i don't see it! Every equation i come up with has an extra variable.

    i have found:
    angle 3 + angle 2 = 60degrees
    DA sin(95deg)=1000sin(angle2)
    or DP sin(120)=1000sin(angle2)
    and DP sin (60deg)=DA sin((95deg)

    and similiar for angle3
     
  7. Oct 30, 2004 #6
    OK...do this:

    Extend out the sides AB and DC until they meet. Then you have another triange there....you can find what that angle is using a couple of equations, then you can use it to find angles 2 and 3
     
  8. Oct 30, 2004 #7
    By "that angle", I am refering to the new angle formed by AB and CD :)
     
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