- #1

LordofDirT

- 15

- 0

This time I have a problem that I believe is easy, but I want to check my answer with you (since there missing in the back of the book) and make sure my notation is correct since I've never taken trig, and class hasn't started yet. So my ramble ends.

If a possitive angle has measure [tex]x^o[/tex] between [tex]0^o[/tex] and [tex]60^o[/tex] how can I represent the first negative angle coterminal with it?

First I drew a diagram to solve it with x as the variable for the positive rotation, and y for the variable for negative rotation. Assuming that they want the measure of the negative angle coterminal (which would be the end of rotation in the negative direction?). So I figured that:

[tex]180^o + 180^o - x^o = y^o[/tex]

[tex]360^o - x^o = y^o[/tex]

First of all how correct is this?

And is this the right way to measure the "first" negative angle coterminal?

Is there a second. This is where I'm lost.