# Trig basics

1. Jun 29, 2005

it was a one semester class, so it is basic. note: i will not cover graphing and inverse trig function.

i will begin by introducing a unit of measurement of angles, because i find them much easier to work with. that unit is radian. the name will make sense after the description. we have a circle whose center is at the origin. as we all know, the circumference of a circle is $$C=2{\pi}r$$. assume the radius of the circle is one. the circumference can be thought of as the full rotation of the radius, so a full rotation is $$2{\pi}=360^0$$. half a rotation is $$\pi=180^0$$. a forth of a rotation is $$\frac{\pi}{2}=90^0$$ and so on. angles are measured from the positive x-axis(initial side) in a counter clockwise manner to the terminal side. negative angles are clockwise. to convert radians to degrees, multiply the radian measurement by $$\frac{180}{\pi}$$. to convert from degrees to radians multpily the degree measurement by $$\frac{pi}{180}$$

every angle has a reference angle($$\alpha\angle$$. a reference angle is the smallest positive acute angle made by the terminal side of $$\theta$$ and the x-axis. in the first quadrant, $$\alpha\angle=\theta$$. in the second quadrant, $$\alpha\angle=\pi-\theta$$. in the third, $$\alpha\angle=\theta-\pi$$. in the fourth, $$\alpha\angle=2\pi-\theta$$. trig functions of $$\theta=\underline{+}same function of \alpha\angle$$

each angle also has an infinite number of coterminal angles. coterminal angles are angles that have the same terminal side(kinda makes sense, huh).coterminal angle=$$\theta\underline{+}n2\pi$$

the trig functions: sin, cos, tan, csc, sec, cot are all ratios of the sides of a right triangle. each angle has a specific value for each of the trig functions.
sin and cos, sec and csc, tan and cot are what are called cofunctions. cofunctions are positive in the same quadrant. in the first quadrant, all functions are positive. in the second, sin and csc are positive. in the third, tan and cot are positive. in the fourth, cos and sec are positive. the trig function of any acute angle equals the cofunction of said angle's complement.

sin and csc, cos and sec, tan and cot are reciprocal functions. that will make sense once you see their definitions and identities

$$sin=\frac{opposite side}{hypotenuse}$$
$$cos=\frac{adjacent side}{hypotenuse}$$
$$tan=\frac{opposite side}{adjacent side}$$
$$csc=\frac{hypotenuse}{opposite side}$$
$$sec=\frac{hypotenuse}{adjacent side}$$
$$cot=\frac{adjacent side}{opposite side}$$

reciprocal identities
$$sin\theta=\frac{1}{scs\theta}$$
$$csc\theta=\frac{1}{sin\theta}$$
$$cos\theta=\frac{1}{sec\theta}$$
$$sec\theta=\frac{1}{cos\theta}$$
$$tan\theta=\frac{1}{cot\theta}$$
$$cot\theta=\frac{1}{tan\theta}$$

ratio identites
$$tan\theta=\frac{sin\theta}{cos\theta}$$
$$cot\theta=\frac{cos\theta}{sin\theta}$$

pythagorean identities
$$sin^2\theta+cos^2\theta=1$$
$$1+tan^2\theta=sec^2\theta$$
$$1+cot^2\theta=sec^2\theta$$

cofunction identities
$$sin(\frac{\pi}{2}-\theta)=cos\theta$$
$$cos(\frac{\pi}{2}-\theta)=sin\theta$$
$$cos(\frac{\pi}{2}-\theta)=sin\theta$$
$$tan(\frac{\pi}{2}-\theta)=cot\theta$$
$$cot(\frac{\pi}{2}-\theta)=tan\theta$$
$$sec(\frac{\pi}{2}-\theta)=csc\theta$$
$$scs(\frac{\pi}{2}-\theta)=sec\theta$$

Last edited: Jun 29, 2005
2. Jun 29, 2005

### Jameson

My browser cannot load half of the Latex graphics. I don't know if that's just myself.

I like how you are going over basic trig, but it seems to be a lot of formulas and no so much explaining. Perhaps if you derived the formulas, it would be more helpful. Keep it up.

Jameson

EDIT: When writing plain text in Latex, use this: \mbox{} . It looks nicer.

3. Jun 29, 2005

maybe i should break it up.

with formulas you don't really need a lot of explaining. if anyone has questions, just ask.

4. Jun 29, 2005

even/odd identities
$$sin(-\theta)=-sin\theta$$
$$cos(-\theta)=cos\theta$$
$$tan(-\theta)=-tan\theta$$
$$csc(-\theta)=-csc\theta$$
$$sec(-\theta)=sec\theta$$
$$cot(-\theta)=-cot\theta$$

solving triangles(side a is opposite anlge alpha; side b is opposite angle beta; side c is opposite angle gamma)
law of sines-$$\frac{a}{sin\alpha\frac{b}{sin\beta}=\frac{c}{sin{\gamma}}$$
law of cosines-$$c^2=a^2+b^2-2abcos\gamma$$ *note: when gamma is a right angle, law of cosines turns into pythagorean theorem*

area of triangles
$$A=\frac{1}{2}absin\gamma$$
$$A=\sqrt{s(s-a)(s-b)(s-c)}$$, when $$s=\frac{a+b+c}{2}$$

now that you have all of that, here are some formulas

double angle formulas
$$sin2\theta=2sin\thetacos\theta$$
$$cos2\theta=cos^2\theta-sin^2\theta$$
$$cos2\theta=1-2sin^2\theta$$
$$cos2\theta=2cos^2\theta-1$$
$$tan2\theta=\frac{2tan\theta}[1-tan^2\theta}$$

half angle formulas
$$sin\frac{\theta}{2}=\sqrt{\frac{1-cos\theta}{2}}$$
$$cos\frac{\theta}{2}=\sqrt{\frac{1+cos\theta}{2}}$$
$$tan\frac{\theta}{2}=\sqrt{\frac{1-cos\theta}{1+cos\theta}}$$
$$tan\frac{\theta}{2}=\frac{1-cos\theta}{sin\theta}$$
$$tan\frac{\theta}{2}=\frac{sin\theta}{1+cos\theta}$$

power reducing formulas
$$sin^2\theta=\frac{1-cos2\theta}{2}$$
$$cos^2\theta=\frac{1+cos2\theta}{2}$$
$$tan^2\theta=\frac{1-cos2\theta}{1+cos2\theta}$$

sum and difference formulas
$$sin(\alpha+\beta)=sin\alphacos\beta+cos\alphasin\beta$$
$$sin(\alpha-\beta)=sin\alphacos\beta-cos\alphasin\beta$$
$$cos(\alpha+\beta)=cos\alphacos\beta-sin\alphasin\beta$$
$$cos(\alpha-\beta)=cos\alphacos\beta+sin\alphasin\beta$$
$$tan(\alpha+\beta)=\frac{tan\alpha+tan\beta}{1-tan\alphatan\beta}$$
$$tan(\alpha-\beta)=\frac{tan\alpha-tan\beta}{1+tan\alphatan\beta}$$

sum and difference to product formulas
$$sin\alpha+sin\beta=2sin\frac{1}{2}(\alpha+\beta)cos\frac{1}{2}(\alpha-\beta)$$
$$sin\alpha-sin\beta=2cos\frac{1}{2}(\alpha+\beta)sin\frac{1}{2}(\alpha-\beta)$$
$$cos\alpha+cos\beta=2cos\frac{1}{2}(\alpha+\beta)cos\frac{1}{2}(\alpha-\beta)$$
$$cos\alpha-cos\beta=-2sin\frac{1}{2}(\alpha+\beta)sin\frac{1}{2}(\alpha-\beta)$$

Last edited: Jun 29, 2005
5. Jun 29, 2005

product to sum and difference formulas
$$sin\alphasin\beta=\frac{1}{2}[cos(\alpha-\beta)+cos(\alpha+\beta)]$$
$$cos\alphacos\beta=\frac{1}{2}[cos(\alpha-\beta)+cos(\alpha+\beta)]$$
$$sin\alphacos\beta=\frac{1}{2}[sin(\alpha+\beta)+sin(\alpha-\beta)]$$

6. Jun 29, 2005

### Jameson

I've already taken trig... I don't need the explaining. However, I find that memorizing a formula and not really understanding why isn't good for the student. How do you even konw that these formulas are true? Prove it.

I'm not saying you can't, I just know I like it when my teachers give a little more explanation.

Jameson

7. Jun 29, 2005

### lurflurf

The thing I disliked about basic trig is a complete lack of rigor. There are several ways to define trig functions
1. as solutions to differential equations
2. as infinite series
3. as ratios of triangles
4. as functions of arc lenth traversed on a circle
5. as functions satisfying certain functional relations
1,2 require too much calculus
3,4 require too much geometry and are at great risk of losing rigor in how they define angle measure.
Clearly 5 is the best despite being least common.
Among several ways of presenting 5 a particularlly nice one is
Let sin and cos be the functions R->R which have the following properties
1) sin(x+y)=sin(x)cos(y)+cos(x)sin(y) all x,y in R
2) cos(x+y)=cos(x)cos(y)-sin(x)sin(y) all x,y in R
3) 1=(sin(x))^2+(cos(x))^2 all x in R
4) lim x->0 sin(x)/x=1

Theorem 1 sin and cos exist and are unique
Theorem 2 there exit at least 1 x in R such that sin(x)=cos(x)
Definition pi/4= the smallest positive value such that sin(x)=cos(x)
From here other functions can be defined, other identities derived, and values can be found such as sin(pi/10), cos(pi/12). And all is good in trig land.

8. Jun 30, 2005

### krab

LaTeX notes: (1) precede trig functions with a backslash. LaTeX otherwise cannot tell that sin is not s times i times n. (2) If you have non-math, like "hypotenuse" in a formula, same thing applies: LaTeX thinks it is h times y times.... In these cases, put the English in \mbox{...} (put it where the dots are). Then it is formatted as prose instead of math and in particular, spaces and punctuation are observed. So for example,
$$\sin\theta=\frac{\mbox{opposite side}}{\mbox{hypotenuse}}$$

9. Jul 1, 2005

### Jameson

For the pythagorean identities, you could show that the second two can be derived from the first.

$$\sin^2\theta+\cos^2\theta=1$$

$$\frac{\sin^2{\theta}}{\sin^2{\theta}}+\frac{\cos^2{\theta}}{\sin^2{\theta}}=\frac{1}{sin^2{\theta}}$$

Which leads into the third identity you listed.

$$1+\cot^2{\theta}=csc^2{\theta}$$

Divide the first by $\cos^2{\theta}$ for the second.

Last edited: Jul 1, 2005
10. Jul 1, 2005

it said BASIC...do you know what that means?

Last edited: Jul 1, 2005
11. Jul 1, 2005

### Jameson

Ok, Ok, fair enough. You did say basic.

Also, I cannot view the Latex for the Law of Sines. Perhaps there is an error.

12. Jul 1, 2005

law of sines
$$\frac{a}{\sin{\alpha}}=\frac{b}{\sin{\beta}}=\frac{c}{\sin{\gamma}}$$

13. Jul 1, 2005

### lurflurf

It could mean several things
such as
A programming language.
a pH>7.0
a certain type of rock
I will consider those meanings most likely to apply
The most simple complete form
Who can say which forms are complete or most simple. I would argue that given the geometry background of most students of trigonometry a geometric definition is not complete or simple.
primary importance
The primary importance in trig is debatable, but for me triangle ratios while an interesting and useful application are not primarily important.
a starting point
Certainly any definition could be used as a starting point and hence would be basic.

Basic does not mean easy. Though it is questionable if your style of presenting trig is the easiest (for a typical student), for the sake of argument say it is 10% easier than other methods. That does not mean it is best as other methods might offer a greater than 10% gain in return for the 10% increase in effort.

My key point is that geometric definitions require a notion of arc lenth and/or one of angle measure. These notions are quite obscure at the level of intro to trig. Some would say that drawing a triangle and holding a protrator up to it is sufficient to define angle measure. I am not one of those people. Also there is something to be said for learning something right the first time. Often in eduction there is a push to try and simplify ideas too much. In the end more effort can be expended learning several versions of something than is needed to learn a good version first. These thing need to be carefully considered I do not necessarily think Lebesgue Measure needs to be taught to high school students.

Last edited: Jul 1, 2005
14. Jul 1, 2005

it's called context...please stop the pointless flame...

well, you seem to already have sead notions down, so it doesn't really matter, now does it?

15. Jul 3, 2005

### Cincinnatus

Lurflurf, how would you prove these theorems from the properties you stated?

16. Jul 3, 2005

### lurflurf

Thats the best part!
I will outline it hopefully anyone interested can provide themselves with the details.
Exististance is easy is you cheat a little by considering a pair of functions for a dense subset of the reals defined by f(0)=1 f(pi/2)=0 g(0)=1 g(pi/2)=0 0<f(x),g(x)<1 when 0<x<pi/2. And satisfation of f(x+y)=f(x)f(y)-g(x)g(y) g(x+y)=g(x)f(y)=(f(x)g(y) f(x)^2+g(y)^2=1 will be consistant. Next show lim x->0 f(x)/x=1. Now the limit implies continuity so we define a function on all real by filling in the gaps. In particular we can use n*pi/2^m for n,m integers as the dense subset. For uniquness Assume the pair S(x),C(X) also meet the definition. since lim s(x)/x=1 and lim sin(x)/x=1 lim sin(x)/S(x)=1 consider x> 0 so sin(x) and S(x) do not agree then consider repeated use of half angle identity sin(x/2^n)/S(x/2^n) will not be close to 1 for large n -><-. sin(0)=0 cos(x)=1 and sin(x)^2+cos(x)^2=1 this implies that sin increases and cos decreases at certain rate in an interval (0,b). If they are never equal at some point cos(x)<sin(x) but this cannot happen without them having been equal prior. We can get values for pi/10 and pi/12 by considering sin(5x) and sin(3x) type identities.

17. Jul 4, 2005

### Cincinnatus

Sorry, I don't really understand this proof.
I have never proved this kind of statement before and I am not really sure what must be shown in order to make this kind of conclusion...

Perhaps I don't really know what is meant when you say the functions exist in this sense...

could you perhaps give an example of a set of properties that would define a function that could not exist?

18. Jul 5, 2005

### lurflurf

A function that does not exist would be one whose properties are contradictory. A silly example might be a function where x<f(x) for all x that also has f(x)<1 for all x, 2<f(2)<1 which cannot happen. A slightly less silly example might be |f(x)-f(y)|<(x-y)^2 for all x and y (where x and y are not equal )together with f(2)=1+f(1). A good definition defines something that exist in the sense that it is possible for something to satify all the requirements and is unique in the sense that the definition does not cause confusion in that it implies several non identiacl thins are identical. To prove sin and cos are unique you can start by defining a function that meets some of the requirements. You can cheat a little by using known properties of sin and cos such as sin(pi/4)=cos(pi/4) since for the existance part one is trying to show that it is possible for a functon to have these properties. lim x->0 sin(x)/x=1 implies that sin is continuous so we can define a function on a dense subset of the reals. If two continuous functions on agree on a dense subsets of the reals they agree at all real numbers. So we can define functions on real numbers of the form n*pi/2^m where n and m are integers and this will be a dense subset. We do this by letting C(0)=S(pi/2)=1 and C(pi/2)=S(0)=1 where C(x) and S(x) are prototypes of trig functions in a sense. Then the relations
C(x+y)=C(x)C(y)-S(x)S(y)
S(x+y)=S(x)C(y)+C(x)S(y)
(S(x))^2+(C(x))^2=1
are used do define the functions are all real numbers of the form n*pi/2^m
Since these relations were used in defining the functions they are consistent. Finally it is shown that lim x->0 sin(x)/x=1
Finally we extend the definition to all real numbers filling in gaps that is by requireing the functions to be continuous. This is the same method used for introducing irrational exponents in high school algebra. x^(m/n) is defined for n,m integers (n>0) thus making sure x^r is continuous defines x^r for r a real number. An interesting note is pi is used about but an unknow constant could be used, then during the work one would learn that the constant is pi.

19. Jul 6, 2005

### pl_terranine

i have 2 questions. how were trigonometric tables made back then? I couldn't just divide sin(45) in half to get sin(22.5) so i was wondering what techniques they used.

20. Jul 6, 2005

### lurflurf

What do you mean by back then? If you know the values for 18 degrees and 15, then you can find the values for multiples of 3 degrees. You can use half angle formula to get values for multiples of 1.5 degrees. Then you can write values in terms of known values and small values and use.
for small x
sin(x)~x-x^3/6+x^5/120+...
cos(x)~1-x^2/2+x^6/720+...
This assumes that you can calculate the roots in exact values, otherwise you can build up values from small values. Also you could draw large triangles and try to measure it as closely as possible. Of course now we have computers...