[tex]\int \frac {x^2}{\sqrt{4x-x^2}}dx[/tex](adsbygoogle = window.adsbygoogle || []).push({});

I just want to be sure I'm right on this, complete the square first of all so you get [tex]-\int \frac {x^2}{\sqrt{(x-2)^2-4}}dx[/tex] let [tex]u=x-2[/tex] thus [tex]-\int \frac {(x+2)^2}{\sqrt{u^2-4}}dx[/tex]then let[tex] u=2sec(\theta)[/tex]

hence integral becomes [tex]-8\int sec^3(\theta)+2sec^2(\theta)+sec(\theta)d\theta[/tex]

and then solve.

Thanks

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# Trig Derivative

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