Trig Equation

  • Thread starter Imperil
  • Start date
  • #1
39
0
a) Use the special triangles and the CAST rule to solve the equation 2sinx + [tex]\sqrt{3}[/tex] = 0 for the domain interval 0 [tex]\leq[/tex] x [tex]\geq[/tex] 360.

b) What feature of the graph, in the form y = asinx + b, would show the solutions?


My Answers:

a) sinx = -[tex]\sqrt{3}[/tex]/2
x = -60 degrees

180 + 60 = 240 degrees
360 - 60 = 300 degrees

b) Can anybody give me a clue as to what this is asking? I have absolutely no idea :(
 

Answers and Replies

  • #2
35,204
7,010
For b, think about where the graph of y = 2sinx + sqrt(3) crosses the x-axis. I think that's what the problem is getting at.
 
  • #3
39
0
For b, think about where the graph of y = 2sinx + sqrt(3) crosses the x-axis. I think that's what the problem is getting at.
This is what I was thinking of as the graph will cross x at 4Pi/3 and 5Pi/3, so I was thinking that the feature to show the solution would be the x-intercepts.

Is this correct? I originally thought this but then was confused by the words "feature of the graph"
 
  • #4
35,204
7,010
An x-intercept is a feature of a graph. Again, I think this is what the question is getting at.
 

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