Trig equation

  • Thread starter Aaron H.
  • Start date
  • #1
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Homework Statement



Solve, finding all solutions in [0, 2pi)


Homework Equations



sqrt (cot x) = (3)^(1/4)

The Attempt at a Solution



[sqrt (cot x) = (3)^(1/4)]^4 =

sqrt [cot^2 x = 3] =

cot x = +/- sqrt (3)

x = pi/6, 5pi/6, 7pi/6, 11pi/6

the answer choices to this problem only have two angles each, so two of the angles I derived aren't necessary
 

Answers and Replies

  • #2
867
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Since the original problem has (cot x), the solution can't include the values corresponding to cot x = -√3.
 

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