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Trig Equation

  1. Oct 24, 2005 #1
    Looking for some help for this equation:

    [tex]2 \csc x + 3 \sec x = - \sec x \tan x[/tex]
  2. jcsd
  3. Oct 24, 2005 #2


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    Generally, for a problem like this, the best thing to do is change them all to one function. Do you know how sec x, csc x and tan x are defined?
  4. Oct 30, 2005 #3
    I do. I can put it all in sine/cosine but I can't get anywhere from there.

    [tex]\frac{2}{\sin x} + \frac{3}{\cos x} = -\frac{1}{\cos x}\cdot\frac{\sin x}{\cos x}[/tex]
    Last edited: Oct 30, 2005
  5. Oct 30, 2005 #4


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    So, what's the question? Is this an identity that you are trying to prove, or are you trying to solve for x that satisfies the equation?
    Last edited: Oct 30, 2005
  6. Oct 30, 2005 #5
    Solve for x.
  7. Oct 30, 2005 #6


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    HallsofIvy had the right idea. You just need to go further. Which trig function could you multiply by to simplify the equation [itex]\frac{2}{\sin x} + \frac{3}{\cos x} = -\frac{1}{\cos x}\cdot\frac{\sin x}{\cos x}[/itex]?
    Last edited: Oct 30, 2005
  8. Oct 30, 2005 #7
    Sine! Thanks.
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