- #1

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Looking for some help for this equation:

[tex]2 \csc x + 3 \sec x = - \sec x \tan x[/tex]

[tex]2 \csc x + 3 \sec x = - \sec x \tan x[/tex]

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- Thread starter cscott
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- #1

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Looking for some help for this equation:

[tex]2 \csc x + 3 \sec x = - \sec x \tan x[/tex]

[tex]2 \csc x + 3 \sec x = - \sec x \tan x[/tex]

- #2

HallsofIvy

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- #3

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HallsofIvy said:

I do. I can put it all in sine/cosine but I can't get anywhere from there.

[tex]\frac{2}{\sin x} + \frac{3}{\cos x} = -\frac{1}{\cos x}\cdot\frac{\sin x}{\cos x}[/tex]

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- #4

hotvette

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cscott said:Looking for some help for this equation:

[tex]2 \csc x + 3 \sec x = - \sec x \tan x[/tex]

So, what's the question? Is this an identity that you are trying to prove, or are you trying to solve for x that satisfies the equation?

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hotvette said:So, what's the question? Is this an identity that you are trying to prove, or are you trying to solve for x that satisfies the equation?

Solve for x.

- #6

hotvette

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HallsofIvy had the right idea. You just need to go further. Which trig function could you multiply by to simplify the equation [itex]\frac{2}{\sin x} + \frac{3}{\cos x} = -\frac{1}{\cos x}\cdot\frac{\sin x}{\cos x}[/itex]?

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- #7

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hotvette said:HallsofIvy had the right idea. You just need to go further. Which trig function could you multiply by to simplify the equation [itex]\frac{2}{\sin x} + \frac{3}{\cos x} = -\frac{1}{\cos x}\cdot\frac{\sin x}{\cos x}[/itex]?

Sine! Thanks.

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