# Trig equations

1. Mar 7, 2006

### Hootenanny

Staff Emeritus
The question is to solve the equation;
$$2\cot^{2}x + 7cosec x - 13 = 0$$
for all values of x between 0 and 360. I know I need to use a trig ident, but I've been using several over the course of an hour and I can't seem to get anywhere. Any hints would be helpful

2. Mar 7, 2006

### vaishakh

Multiply with sin^2x

3. Mar 7, 2006

### Lyuokdea

try using cot(x)^2 + 1 = csc(x)^2

~Lyuokdea

4. Mar 7, 2006

### Hootenanny

Staff Emeritus
Thank's got it.