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Trig equations

  1. Mar 7, 2006 #1

    Hootenanny

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    The question is to solve the equation;
    [tex]2\cot^{2}x + 7cosec x - 13 = 0 [/tex]
    for all values of x between 0 and 360. I know I need to use a trig ident, but I've been using several over the course of an hour and I can't seem to get anywhere. Any hints would be helpful
     
  2. jcsd
  3. Mar 7, 2006 #2
    Multiply with sin^2x
     
  4. Mar 7, 2006 #3
    try using cot(x)^2 + 1 = csc(x)^2

    ~Lyuokdea
     
  5. Mar 7, 2006 #4

    Hootenanny

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    Thank's got it.
     
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