# Trig Equations

1. Nov 18, 2007

### rum2563

1. The problem statement, all variables and given/known data
Solve for x.
tan(2x) = 8cos(x)^2 - cot(x) where x is between 0 to 90 degrees.

2. Relevant equations
tan(2x) = 2tan(x)/1-tan(x)^2
cot(x) = 1/tan(x)

3. The attempt at a solution

tan(2x) = 8cos(x)^2 - cot(x)
2tan(x)/1-tan(x)^2 + 1/tan(x) = 8cos(x)^2
(2tan(x)^2 + (1-tan(x)^2))/(tan(x)-tan(x)^3) = 8cos(x)^2

I am stuck at this point. Any help would be great since this is due tomorrow. Thanks.

2. Nov 18, 2007

### rocomath

$$\tan{2x}=8\cos^{2}x-\cot{x}$$

correct? just making sure, i'm not really sure about your 2nd term.

3. Nov 18, 2007

### rum2563

Yes, you are correct.