1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Trig equations

  1. Jul 26, 2011 #1
    1. The problem statement, all variables and given/known data

    I dont understand how to solve for these, I will post 3.

    d) [sqrt]2sin x + 1 = 0 (sqrt only over the 2)
    e) 2cos x - [sqrt]3 = 0
    f) 2sinx +[sqr]3 = 0

    Esentially, I dont understand how to get the degrees. I dont get how you use the terminal arm to predict the degrees, etc.

    Can anyone help?



    2. Relevant equations



    3. The attempt at a solution

    1 / [sqrt]2

    sin inverse of that is 30 degrees.

    which is pi over 6.

    How do i get the second one? how do i know? etc
     
  2. jcsd
  3. Jul 26, 2011 #2

    rock.freak667

    User Avatar
    Homework Helper

    I am assuming you are finding from 0 to 2pi.

    For the three you are doing the same thing, making sinx or cosx the subject of the formula and then taking the inverse function of it.

    The first one you did partially right

    sinx = 1/√2 and x=sin-1(1/√2)

    Check back on your calculator for what value this is.

    When you get that what quadrant is sine positive in?
     
  4. Jul 27, 2011 #3

    Ray Vickson

    User Avatar
    Science Advisor
    Homework Helper

    Write sqrt(2) instead of [sqrt]2, etc; that way, you don't have to make statements like "sqrt only over the 2". Anyway, if you know elementary Geometry, you should be able to see what angles give you sin(x) = -1/sqrt(2), cos(x) = 3/sqrt(2) and sin(x) = -sqrt(3)/2. I realize that Geometry may not be taught anymore in schools, in which case you can do a Google search on something like "sines of special angles" to find some material.

    RGV
     
  5. Aug 2, 2011 #4
    4f) cosx =2sincosx

    How do you solve this?

    The only thing i see is

    ..cosx - cosx- = 2sin

    is that wrong?

    does that mean cos is 0 and sin is 90+90 = 180 degrees?
     
  6. Aug 2, 2011 #5

    rock.freak667

    User Avatar
    Homework Helper

    bring the cosx on the left side to the right side and then factor out the cosx.
     
  7. Aug 2, 2011 #6
    Does that not equal the exact same thing? cos is 0 and sin is 180?
     
  8. Aug 2, 2011 #7

    rock.freak667

    User Avatar
    Homework Helper

    You mean x=0, x=180? if so, by putting x=0 into the equation you will see that it is not a solution.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Trig equations
  1. Trig Equation (Replies: 3)

  2. Trig equation (Replies: 1)

  3. Trig equation (Replies: 4)

  4. Trig. Equation (Replies: 8)

  5. Trig equation (Replies: 10)

Loading...