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Trig functions behaviour

  • Thread starter aisha
  • Start date
584
0
Hi just need a little help with the behaviour of this trig function

[tex] y=-3\cos (2x-\frac {\pi} {6}) +1 [/tex]
I converted the pi over 6 to degrees and got -30

need to state the period, amplitude, max/min values, range, domain, horizontal phase shift, and vertical dispacement.

So far after rearranging the the equation i have

period= [tex] pi [/tex]
range= ????
amplitude=?????
domain= all values XER
horizontal phase shift= 15 degrees left
vertical displacement= up 1
max\min ??? :redface: not sure how to figure this out from the equation i tried graphing using the graphing calculator but it wont give me the values for max and min. Therefore I cannot solve for amplitude yet and same with range.

CAN SOMEONE PLEASE HELP ME JUST NEED HELP WITH THE MAX AND MIN THANKS :blushing:
 

Answers and Replies

584
0
I got
max = 4, min = -2
amplitude = 3
range = {y:-2 <= y <= 4}

is this correct or have i done something wrong..please check and reply soon! :blushing:
 
Fermat
Homework Helper
872
1
what are the max and min values of the cos function?
Use that to figure out the max and min values of y.
 
Fermat
Homework Helper
872
1
aisha said:
I got
max = 4, min = -2
amplitude = 3
range = {y:-2 <= y <= 4}

is this correct or have i done something wrong..please check and reply soon! :blushing:
yes, those are correct.
 
584
0
is everything else correct too the period domain and shifts?
 
Fermat
Homework Helper
872
1
Yes - everything else looks ok.
 

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