First, start off by writing secant as a cosine function:
[tex]\frac{1}{\cos A}=1.2048[/tex]
Now, solve the function for A. Remember, [itex]\arccos A[/itex] is only defined from 0 to [itex]\pi[/itex] so you have to find a corresponding angle between [itex]\pi[/itex] and [itex]2\pi[/itex]
This question would make more sense if asked about the range from 0 to [itex]2\pi[/itex], since there would be two angles with sec = 1.2048. But there's only one in the range of [itex]\pi[/itex] to [itex]2\pi[/itex], so the question doesn't make that much sense.
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