Trig identity limit

  • Thread starter synergix
  • Start date
  • #1
178
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Homework Statement



lim t3/tan32t
t->0

The Attempt at a Solution



I am stuck I have alot of trouble with trig identities
 

Answers and Replies

  • #2
867
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Do you know L'hôpital's rule? That might be the easiest way. If not, rewrite tan2t as sin2t/cos2t first. cos(2*0) won't cause a problem, but the t and sin2t will. See if you can get it to look like sin2t/t.
 
  • #3
178
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lim= 2*t*2*t*2*t*cos32t/2*sin2t*2*sin2t*2*sin2t\


so all the 2*t cancel the sin2t leaving cos32t/2*2*2 so limit=1/6

is this correct??
 
  • #4
867
0
2*2*2=8, not 6. :wink:
 
  • #5
178
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haha ya wow. :)
 

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