- #1

Bradyns

- 20

- 0

[itex]\frac{CosθSinθ}{1 + Tanθ}[/itex] = Cos

^{2}θ

===========================

I multiply out the denominator to get:

CosθSinθ = Cos

^{2}θ + CosθSinθ

I cannot seem to prove it.

Starting to think it's a trick question.. :/

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- Thread starter Bradyns
- Start date

- #1

Bradyns

- 20

- 0

[itex]\frac{CosθSinθ}{1 + Tanθ}[/itex] = Cos

===========================

I multiply out the denominator to get:

CosθSinθ = Cos

I cannot seem to prove it.

Starting to think it's a trick question.. :/

- #2

krome

- 37

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- #3

Millennial

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