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Trig identity

  1. Nov 18, 2008 #1
    1. The problem statement, all variables and given/known data
    k=[tex]\frac{1+sinx}{cosx}[/tex]
    prove that [tex]\frac{1}{k}[/tex]=[tex]\frac{1-sinx}{cosx}[/tex]

    thanks in advance:smile:

    2. Relevant equations



    3. The attempt at a solution
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
    i tried substitution of 1 with
    cos^2(x)+sin^2(x) and
    cosec^2(x)-cot^2(x) and
    sec^2(x)-tan^2(x)

    but im stucked agn..
     
  2. jcsd
  3. Nov 18, 2008 #2

    gabbagabbahey

    User Avatar
    Homework Helper
    Gold Member

    Start by inverting your expression for k to get: [tex]\frac{1}{k}=\frac{\cos x}{1+\sin x}[/tex] ...then multiply both your numerator and denominator by [itex](1- \sin x)[/itex] and simplify...what do you get?
     
  4. Nov 19, 2008 #3
    oh..yah.. thanks loads. i will get the answer!
     
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