# Trig identity

## Homework Statement

k=$$\frac{1+sinx}{cosx}$$
prove that $$\frac{1}{k}$$=$$\frac{1-sinx}{cosx}$$

## The Attempt at a Solution

i tried substitution of 1 with
cos^2(x)+sin^2(x) and
cosec^2(x)-cot^2(x) and
sec^2(x)-tan^2(x)

but im stucked agn..

Start by inverting your expression for k to get: $$\frac{1}{k}=\frac{\cos x}{1+\sin x}$$ ...then multiply both your numerator and denominator by $(1- \sin x)$ and simplify...what do you get?