1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Trig id's and fourier

  1. Jan 11, 2004 #1

    teo

    User Avatar

    hi, first off just have to say these boards kick serious ass!!! Too much interesting posts on here, really like the Mechanical eng board since thats what im doing at uni :)

    Right, to the problem,

    I do the integral and get the below answer,

    Bn = 1/pi [-Cos nt/n] between pi/2 and 0
    Bn = 1/pi [[-Cos n(pi/2)/n]-1/n]

    but then my notes skip from this to another line,

    Bn = 1/npi [1-Cos nt]

    The n gets taken out and 1 comes from Cos n0 but why do the signs change?
     
  2. jcsd
  3. Jan 11, 2004 #2

    teo

    User Avatar

    LOL just looked at it again, and i forgot that there's a minus infront of the cos nt/n which makes

    Bn = 1/npi [(-cos nt)-(-1)]

    which answers my question :)
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Trig id's and fourier
  1. ID a particle (Replies: 2)

  2. Trig trig trig (Replies: 11)

Loading...