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Trig in equation

  1. Jan 18, 2007 #1
    i am unsure about how to rearrange this equation so that I can solve for x an unknown angle. Please help.

    we have:

    sin^2 x(tan x)=1356

    it is very simple I no but I just can't remember the way to go about solving this problem, especially because of the sin^2
     
  2. jcsd
  3. Jan 18, 2007 #2
    Follow the steps below:

    1. [tex] tan(x) = \frac{sin(x)}{cos(x)} [/tex]
    2. [tex] cos(x) = \sqrt{1 - sin^2(x)} [/tex]
    3. take square on both size, and re-arrange the terms, you will get a 6th order polynomial
    4. do a substitution [tex] y = sin^2(x) [/tex], then you will have a 3th order polynomial
    5. solve the 3rd order polynomial for y.....
    6. as soon as you have y, you will get x... (make sure x is not a single value function of y)
     
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