Yes, solving tan(x/2)= -1 is the way to start. On any interval NOT including a root of tan(x/2)= -1 and NOT including [itex]\pi[/itex], where tan(x/2) is not continuous, tan(x/2) is always less than -1 or always less than -1. Determine what those intervals are and check one point in each interval to see if tan(x/2), on that interval, is greater than -1.1. The problem statement, all variables and given/known data
Given 0≤x<2pi, solve tan x/2 > -1
3. The attempt at a solution
I thought I would set tan x/2=-1 but I'm not sure.
Is the answer 0<x<pi, 3pi/2<x<2pi?
Yes, you're right. I don't want to mess with k values.Your first answer is closer than your second answer. If you're restricted to [0, 2pi) then there's no need to mess with the k values.
Two hints: cos(0) = 1 and cos(pi) = -1