- #1
dorkee
- 7
- 0
Homework Statement
Given 0≤x<2pi, solve tan x/2 > -1
The Attempt at a Solution
I thought I would set tan x/2=-1 but I'm not sure.
Is the answer 0<x<pi, 3pi/2<x<2pi?
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Yes, solving tan(x/2)= -1 is the way to start. On any interval NOT including a root of tan(x/2)= -1 and NOT including [itex]\pi[/itex], where tan(x/2) is not continuous, tan(x/2) is always less than -1 or always less than -1. Determine what those intervals are and check one point in each interval to see if tan(x/2), on that interval, is greater than -1.dorkee said:Homework Statement
Given 0≤x<2pi, solve tan x/2 > -1
The Attempt at a Solution
I thought I would set tan x/2=-1 but I'm not sure.
Is the answer 0<x<pi, 3pi/2<x<2pi?
romolo said:Your first answer is closer than your second answer. If you're restricted to [0, 2pi) then there's no need to mess with the k values.
Two hints: cos(0) = 1 and cos(pi) = -1
The range of values for x in the equation is between 0 and 2pi, meaning x can be any value greater than 0 and less than 2pi.
You can determine when tan x/2 is greater than -1 by looking at the graph of the tangent function. When the graph is above the x-axis, the value of tan x/2 is greater than -1.
Yes, you can use a calculator to solve for x. Simply input the equation into your calculator and solve for x using the appropriate buttons or functions.
The restriction 0 To solve for x in this equation, you can use algebraic techniques such as factoring, substitution, or simplifying the equation. You can also use a graphing calculator to find the intersection points of the tangent function and the line y=-1, which will give you the solutions for x.5. How do I solve for x in this equation?
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