- #1
Ayesh
- 29
- 0
Homework Statement
When I look at the equation, I see a trig integral.
[tex]\int[/tex]sinxcos3x/[tex]\sqrt{1+(sin^2)x}[/tex] dx
But the [tex]\sqrt{1++(sin^2)x}[/tex] gets me confused.
I could tranform it into cos2x if it was sin2x - 1
The Attempt at a Solution
[tex]\int[/tex]sinxcos3x/[tex]\sqrt{1++(sin^2)x}[/tex] dx
=[tex]\int[/tex]sintxcos2xcosx/[tex]\sqrt{1++(sin^2)x}[/tex]
=[tex]\int[/tex]sinx - sin2x/[tex]\sqrt{1++(sin^2)x}[/tex]
=...?