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Trig integral

  1. Oct 27, 2006 #1
    evaluate the indefinite integral cos^4(x)sin(x)dx

    I tried using the half angle formula but this gives me a much more difficult integral, so i resorted to just regular substitution but am not sure if I can do this.

    u = cos(x)
    du = -sin(x)dx

    indefinite integral -u^4du

    then -1/5(u)^5 + C or -1/5(cos^5) + C

  2. jcsd
  3. Oct 27, 2006 #2
    That's correct.
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