# Trig integral

1. Oct 27, 2006

### sapiental

evaluate the indefinite integral cos^4(x)sin(x)dx

I tried using the half angle formula but this gives me a much more difficult integral, so i resorted to just regular substitution but am not sure if I can do this.

u = cos(x)
du = -sin(x)dx

indefinite integral -u^4du

then -1/5(u)^5 + C or -1/5(cos^5) + C

thanks!!

2. Oct 27, 2006

### neutrino

That's correct.