1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Trig integral

  1. Jul 3, 2009 #1
    1. The problem statement, all variables and given/known data


    I(tan^3x/cos^4x,x)
    I(tan^3x * sec^4x,x)
    I((sec^2x-1)sec^4x*tanx,x)
    u=secx du=secxtanx
    I((u^2-1)u^3,u)
    u^6/6-u^4/4+C
    sec^6x/6-sec^4x/4+C

    im new to this and my book is showing diffrent solutions i see nothing wrong here
    2. Relevant equations



    3. The attempt at a solution
     
    Last edited: Jul 3, 2009
  2. jcsd
  3. Jul 3, 2009 #2
    Your answer is correct. What is the solution from your book?
     
  4. Jul 3, 2009 #3
    tan^6x/6+tan^4x/4+C
     
  5. Jul 3, 2009 #4
    Are you sure the two solutions are different? (By more than just adding a constant.)
     
  6. Jul 3, 2009 #5
    That answer is also correct. You can get that answer from yours by using sec2 = tan2x + 1, multiplying out the numerators, and simplifying.

    The answer you got seems to be the easiest integral to find for the problem.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Trig integral
  1. Trig Integration (Replies: 2)

  2. Trig Integral (Replies: 7)

  3. Trig. Integral (Replies: 2)

  4. Trig Integral (Replies: 7)

  5. Integration with trig (Replies: 6)

Loading...