I'm still trying to figure out how to do limits of trig functions and I would like to know if this is the correct approach. I know the answer is correct, but not sure if that is just a coincidence. 1. The problem statement, all variables and given/known data lim (x -> 0) of (sin 2x) / (sin3x). 2. Relevant equations 3. The attempt at a solution First I try to get the equation into the form (sin x) / x or x / (sin x) so I multiply by (x/x)(3/3)(2/2) this gives me (1/3)(3x/sin3x)(2/1)(sin2x/2x) so I get (1/3)(1)(2/1)(1) = 2/3 Is that the correct approach?