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Trig limit.

  1. Dec 4, 2011 #1
    1. The problem statement, all variables and given/known data
    Find the value of [tex]\lim_{x \to 0}\frac{cosx - \sqrt{1 + sin^{2}x}}{x^{2}}[/tex]


    2. Relevant equations
    N/A


    3. The attempt at a solution
    The answer is 1/2, but I don't know how they got that. I've tried using double angle formulas and multiplying by the conjugate but I get nowhere. How should I attempt to simplify this limit?
     
  2. jcsd
  3. Dec 4, 2011 #2
    I don't think the limit is 1/2.

    Are you allowed to use L'Hopital's rule?
     
  4. Dec 4, 2011 #3
    It's a past test question and for this test it wasn't allowed to be used, but even then, L'hopital's rule doesn't give 1/2 which is the answer on answer sheet.
     
  5. Dec 4, 2011 #4

    SammyS

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    That limit is -1 .

    To do it without L'Hôpital's rule, multiply the numerator & denominator by [itex]\displaystyle \cos(x) + \sqrt{1 + \sin^{2}(x)}[/itex]

    The numerator then becomes -2sin2(x)
     
  6. Dec 4, 2011 #5

    Curious3141

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    Or alternatively employ cos x ~ (1 - 0.5x^2) and sin x ~ x, and Binomial theorem to the first order on the numerator.
     
  7. Dec 4, 2011 #6
    The answer threw me off, but I used the same method you did Sammy.

    Just one last question: Are there limits that would be in indeterminate form but cannot be simplified by using L'hopital's rule? If yes, could you give an example and how would one proceed to determine whether L'hopital's rule works for a simplifying a certain limit or not?
     
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