- #1
martint
- 9
- 0
Hello,
I've been trying to solve the following but with no luck its so frustrating!
if c= (n/pi) arccos [(n/pi)sin(pi/n)] + 2k(pi), where n is a positive integer,
how can I show that c has precisely one solution in (0,1)?
Thanks!
I've been trying to solve the following but with no luck its so frustrating!
if c= (n/pi) arccos [(n/pi)sin(pi/n)] + 2k(pi), where n is a positive integer,
how can I show that c has precisely one solution in (0,1)?
Thanks!