# Trig Problem

1. Oct 4, 2004

Hello all:

I am stuck on this problem:

From a ship offshore, the angle of elevation of a hill is 1.1 degrees. After the ship moves inland at 4.5 knots for 20 min, the angle of elevation is 1.4 degrees. How high is the hill? (1 knor = i nautical mile per hour = 6080 feet approx)

I first drew a horizontal line. I know 20 min is 1/3 of an hour, so the ship traveled 1.5 knots inland. Basically I have a right triangle consisting of two triangles with the two angle of elevations, and also know that the length of one of the sides of a triangle is 1.5. How would I solve for the height? Would I use the law of sines or cosines?

Any help would be appreciated

Thanks!

2. Oct 4, 2004

### Leong

$$tan\ 1.1^0=\frac{x}{1.5+y}$$
$$tan\ 1.4^0=\frac{x}{y}$$
Solve for x.

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Last edited: Oct 4, 2004