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**[SOLVED] Trig question**

Hi, I'm working on some trig questions and can't get the answer for this last question; I have a hunch that it might be one of those obvious ones where you think too much :uhh: ....

Either way, help would be much appreciated!

solve (cosx)^2 - 2sinxcosx - (sinx)^2 = 0, 0 ≤ x ≤ 2π giving the answer in exact form