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Trig question

  • Thread starter alpha01
  • Start date
77
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find all solutions to sin^2 x = 1/4 in pi/2 <= x < 2pi (i.e in quadrants 2,3 and 4)


i understand what i need to do but dont understand sin^2 part. will i need to apply pythagoras therom here first?



thanks
 

Answers and Replies

458
0
[tex]\sin ^2x=(\sin x)^2[/tex]

You can square root both sides, and finding x should be simple then.
 

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