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Trig solution, tanx+secx=1

  1. Jul 17, 2011 #1
    1. The problem statement, all variables and given/known data

    2. Relevant equations

    3. The attempt at a solution
    tanx=1-secx then square both sides???
    [tex]\tan^2 x= 1-2\sec x+\sec^2 x[/tex][tex]\sec^2 x-1=1-2\sec x+\sec^2 x[/tex][tex]2-2\sec x=0[/tex][tex]\sec x=0[/tex] No Solution
  2. jcsd
  3. Jul 17, 2011 #2


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    2 -2sec(x)=0 gives sec(x)=1, not 0.
  4. Jul 17, 2011 #3
    Thanks, I was trying to factor out a 2 when,
    I should have subtracted 2 then divided by 2, getting sec(x)=1
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