1. The problem statement, all variables and given/known data Solve for x, 0 degress (is less than or equal to) x (is less than or equal to) 360 degrees. Give your answer to the nearest tenth of a degree. Use tables or a calculator when necessary. 1. tan (x+15 degrees)=1 2. sec (x-5 degrees)=2 2. Relevant equations sec= 1/cos Isolating the variable... 3. The attempt at a solution Ok so there's only one part thats tripping me up. But first let me show you my work #1 tan x= 1- 15 degrees tan^-1 (1)=45 degrees 45 degrees - 15 degrees= 30 degrees Tangent is positive in the first and third quadrant, I have the first, so I obtain my third quadrant angle by 180 deg+30 deg=210 ANSWER: 30,210 (this wasn't the one I was having problems with, but I'd be elated if someone could verify my answer) #2 sec x= 2+ 5 degrees (1/cos) x= 2 + 5 deg entire group to the negative first power, which gives me cosine. This is the part I am unsure of. Do I raise the degree portion (5 deg) to the negative first as well, or do I exempt it? I chose to include, which yields cos x= (1/2) + .2 deg cos x^-1(1/2)=60 deg +.2 deg 60.2 deg in the first quadrant. Cosine is positive in the first and fourth quadrant. I obtain the fourth quadrant value by 360-60.2 deg=299.8 degrees ANSWER: 60.2,299.8 degrees But anyway my question is highlighted in the bolded row. Help much appreciated, thanks.