# Trig story problem

1. Mar 20, 2007

### starchild75

1. The problem statement, all variables and given/known data
An airplane flies from Ft. Myers to Sarasota, a distance of 150 miles, and then turns thru an angle of 50 degrees, and flies to Orlando, a distance of 100 miles. How far is it from Fort Myers to Orlando?

2. Relevant equations

Law of Cosines. c^2= a^2 + b^2-2ab cos gamma

3. The attempt at a solution

Using the law of cosines, I squared 150 and added 100 squared. I then subtracted 100 times 150 times cosine of 50 degrees. I then took the square root of c. I got an answer of 114 miles, which cannot be true, having driven in Florida, and also because the diagram shows the route as the hypotenuse. What am I doing wrong?
1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution
1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

2. Mar 20, 2007

### cristo

Staff Emeritus
I suspect the problem is with your angle. Which angle on the diagram is 50 degrees?-- I don't think it's the internal one!

Last edited: Mar 20, 2007
3. Mar 20, 2007

### starchild75

the plane flies north from fort myers to sarasota, then turns 50 degrees to the right, north east toward orlando. Is it the "turning thru an angle" that changes the problem?

4. Mar 20, 2007

### cristo

Staff Emeritus
OK, so the angle 50 degrees is measured from the northerly direction to the direction in which it flies to get to orlando. How do you find out the interior angle of the triangle (i.e. the angle from the southerly direction to the direction in which the plane flies from saratosa to orlando)? This is the angle you need to use the cosine rule.

5. Mar 20, 2007

### starchild75

130 degrees? this gives me an answer of approximately 227.6 miles.?? In looking at the diagram now, it is clear that the turn creates an obtuse angle.

Last edited: Mar 20, 2007
6. Mar 20, 2007

### cristo

Staff Emeritus
Yup, that's what I get.

7. Mar 20, 2007

### starchild75

awesome, thanks.