1. The problem statement, all variables and given/known data integral of (16x-2x^2-23)^1/2 dx 2. Relevant equations 3. The attempt at a solution First off it seems clear that I must complete the square within the radical. This gives ((x-4)^2-4.5)^1/2 From there I seem to be lost, fumbling through my book for any kind of help. Can I use a trig integration, such as using the form (a^2-x^2)^1/2 to substitute x=asecT? I don't think so because (x-4)^2 cannot be treated like x^2. I also cannot find any possible u-sub that will work because of the radical over the entire problem. Any type of guidance is very much appreciated!