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so I did x=atanΘ. which is x=3tanΘ and dx is [tex]3sec^2\Theta[/tex]. Then it is

[tex]\sqrt[]{9tan^2\Theta+9}[/tex]*[tex]3sec^2\Theta[/tex] which evaluates after factoring to [tex]\sqrt[]{9sec^2\Theta}[/tex]*[tex]3sec^2\Theta[/tex] which is then [tex]3sec\Theta*3sec^2\Theta[/tex] If i take the 9 out of the integral, that leaves [tex]sec^3\Theta[/tex]. And i'm stuck

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# Homework Help: Trig Substitution

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