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Trig Substitution

  1. Feb 23, 2010 #1
    http://img708.imageshack.us/img708/8897/symimage.gif [Broken]

    so I did x=atanΘ. which is x=3tanΘ and dx is [tex]3sec^2\Theta[/tex]. Then it is

    [tex]\sqrt[]{9tan^2\Theta+9}[/tex]*[tex]3sec^2\Theta[/tex] which evaluates after factoring to [tex]\sqrt[]{9sec^2\Theta}[/tex]*[tex]3sec^2\Theta[/tex] which is then [tex]3sec\Theta*3sec^2\Theta[/tex] If i take the 9 out of the integral, that leaves [tex]sec^3\Theta[/tex]. And i'm stuck :cry:
    Last edited by a moderator: May 4, 2017
  2. jcsd
  3. Feb 23, 2010 #2


    Staff: Mentor

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