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## Homework Statement

[itex]\int\frac{1}{\sqrt{16-x^2}}dx[/itex]

## Homework Equations

[itex]csc\theta=\frac{4}{\sqrt{16-x^2}}[/itex]

[itex]4cos\theta=x[/itex]

[itex]-4sin\theta d\theta=dx[/itex]

[itex]\theta=arccos(\frac{x}{4})[/itex]

## The Attempt at a Solution

Using these facts, I concluded that the integral, after all of the substitution, was

[itex]-arccos(\frac{x}{4})[/itex] but the actual answer is the arcsin