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first of all, that s not an equation, i dont know the word in english (sorry)

but here... i have to solve that in the interval [-2pi , pi ]

cos(2x)-√3sin(2x) ≥ -√2

here is what i did.....

2(.5cos(2x)-√3 /2 sin(2x) ≥ -√2

cos(pi/3)cos(2x)-sin(pi/3)sin(2x) ≥ -√2 /2

cos(pi/3 + 2x) ≥ -√2 / 2

and that s gonna be....

pi/3 + 2x ≥ pi/4

x ≥ -pi/24

now what, is that all what i have to do? is waht i did right? and finally, what should the solution to this 'problem' be ????

thanks!

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# Trignometric 'equation'

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