(adsbygoogle = window.adsbygoogle || []).push({}); Evaluate [tex]sin(tan^{-1}(\frac{1}{3}))[/tex]

3. The attempt at a solution

Let y = [tex]tan^{-1}(\frac{1}{3})[/tex]

<=> tan(y)=1/3

y = ?

[tex]sin(tan^{-1}(\frac{1}{3})) = sin y[/tex]

I think for solution to exist [tex]tan^{-1}(\frac{1}{3})[/tex] must be in the range of sin, (that is [tex]\left\frac{-\pi}{2}, \frac{\pi}{2}[\right][/tex]

i'm not sure how to evaluate this. :(

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# Homework Help: Trigonometric equation

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