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Trigonometric Functions Graphing

  1. Jan 3, 2004 #1
    Ok I have hit a little bumb in the road on my trigonometric function learning. Ok i need to graph the function y=3cos2(x-120degrees)-3, for x is less than or equal to 360degrees but is greater than or equal to -360degrees. Ok so i know the:
    verticle translation is 3 down
    the phase shift is 120 to the right
    amplitude is 3
    period is 180 degrees
    and so i have the horizontal scale at 15degrees.
    so far so good?

    Ok now here is the one problem, i do not know if i am to go and as sin grpahs go it starts at highest then to middle then lowest then middle then highest and is finished one wave. Well since my hs=15 each line on graph is 15. now i start on 120 as i have to and herei s my question. When i go down to the middle line which would be -3 would it be on the interval of 150degrees or 135 degrees? Or am i doing it wrong as i thought period meant one full wavelength is 180 degrees so it is making me think i am doing it wrong. Please help if possible.
     
  2. jcsd
  3. Jan 4, 2004 #2
    Alright from this equation y=3cos(2(x-120degrees))-3

    I have the rule (.5x+120, 3y-3) is that what you have?
    then with a cosine funtion you start on the y-axis at point (0,1) and then you move to (90, 0) then to (180, -1) then to (270, 0) then to (360, 1) correct? so what you are correct with your beginning point being (120, 0) {thats what you have right} what i normally do when approaching this type of problem is very very basic.. because i am a square who doesnt like to very risky.. i used my rule with an x/y chart. soo...

    original points
    x | y
    0 | 1
    90 | 0
    180 | -1
    270 | 0
    360 | 1

    New rule added ones
    x | y
    120 | 0
    165 | -3
    210 | -6
    255 | -3

    so you are basically adding 45 to the x every time and using 0, -3, and -6 over and over again.. does this answer your question and help you at all. im slightly rusty on all the information on this because i havnt worked with this in about 3months.
     
  4. Jan 4, 2004 #3
    Ok well i figured out what i did wrong so the help isnt needed but thank you anyways
     
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