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Trigonometric identities hard question need help

  1. Jul 29, 2012 #1
    1. The problem statement, all variables and given/known data
    Simplify the following:
    sin(b)/cos(b) + cos(b)/sin(b)


    2. Relevant equations

    Trigonometric identities

    3. The attempt at a solution
    Ok so i have no clue how to do this,I keep trying but can't seem to get the right answer, I have tried to do this:

    sin(b)/cos(b) + cos(b)/sin(b)
    =tan(b)+ 1/tan(b)
    =tan(b)+cot(b)

    I know this isn't right and I am encountering these types of questions quite often now, so I really need help. Please help me.
     
  2. jcsd
  3. Jul 29, 2012 #2

    SammyS

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    Well, it is true that sin(b)/cos(b) + cos(b)/sin(b) = tan(b) + cot(b) , but you probably need to come up with something more surprising.


    Use a common denominator to combine sin(b)/cos(b) + cos(b)/sin(b) into one fraction. Yo may be surprised by what the numerator simplifies to.
     
  4. Jul 29, 2012 #3
    yeah I know it's just that the answer is 1/cos(b)sin(b). How would I get to this?
     
  5. Jul 29, 2012 #4

    SammyS

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    As I said before,
    se a common denominator to combine sin(b)/cos(b) + cos(b)/sin(b) into one fraction. ​
     
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