Trigonometric identities hard question need help

  • Thread starter DJ-Smiles
  • Start date
  • #1
47
0

Homework Statement


Simplify the following:
sin(b)/cos(b) + cos(b)/sin(b)


Homework Equations



Trigonometric identities

The Attempt at a Solution


Ok so i have no clue how to do this,I keep trying but can't seem to get the right answer, I have tried to do this:

sin(b)/cos(b) + cos(b)/sin(b)
=tan(b)+ 1/tan(b)
=tan(b)+cot(b)

I know this isn't right and I am encountering these types of questions quite often now, so I really need help. Please help me.
 

Answers and Replies

  • #2
SammyS
Staff Emeritus
Science Advisor
Homework Helper
Gold Member
11,398
1,045

Homework Statement


Simplify the following:
sin(b)/cos(b) + cos(b)/sin(b)

Homework Equations



Trigonometric identities

The Attempt at a Solution


Ok so i have no clue how to do this,I keep trying but can't seem to get the right answer, I have tried to do this:

sin(b)/cos(b) + cos(b)/sin(b)
=tan(b)+ 1/tan(b)
=tan(b)+cot(b)

I know this isn't right and I am encountering these types of questions quite often now, so I really need help. Please help me.
Well, it is true that sin(b)/cos(b) + cos(b)/sin(b) = tan(b) + cot(b) , but you probably need to come up with something more surprising.


Use a common denominator to combine sin(b)/cos(b) + cos(b)/sin(b) into one fraction. Yo may be surprised by what the numerator simplifies to.
 
  • #3
47
0
yeah I know it's just that the answer is 1/cos(b)sin(b). How would I get to this?
 
  • #4
SammyS
Staff Emeritus
Science Advisor
Homework Helper
Gold Member
11,398
1,045
yeah I know it's just that the answer is 1/cos(b)sin(b). How would I get to this?

As I said before,
se a common denominator to combine sin(b)/cos(b) + cos(b)/sin(b) into one fraction.​
 

Related Threads on Trigonometric identities hard question need help

Replies
2
Views
5K
  • Last Post
Replies
3
Views
1K
  • Last Post
Replies
3
Views
2K
  • Last Post
Replies
4
Views
647
  • Last Post
Replies
5
Views
1K
J
  • Last Post
Replies
2
Views
2K
  • Last Post
Replies
1
Views
2K
  • Last Post
Replies
5
Views
2K
Replies
5
Views
770
  • Last Post
Replies
5
Views
4K
Top